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When running Online DiSC Classic 2.0 Profiles and DiSC Classic 2 Plus Profiles in your EPIC Account, you have the ability to turn on or off Graphs 1 and 2, and the tally box scores.
![Disk Disk](https://www.njuskalo.hr/image-bigger/asus-prijenosnici/asus-x553m-intel-quad-core-4gb-1tb-hdd-intel-graph-gar-2god-1790kn-slika-61402370.jpg)
Graph I is the Adapting Style. It is a ones perception of the behavioral tendencies they think they should use in their selected focus (work, social or family). This graph may change in different environments. For example, if someone responded to the assessment with a work focus, their Adapting Style may be different than if they. Graph I is the Adapting Style. It is a ones perception of the behavioral tendencies they think they should use in their selected focus (work, social or family). This graph may change in different environments. For example, if someone responded to the assessment with a work focus, their Adapting Style may be different than if they.
First, a little information about each of the graphs:
Graph 1: These are your “Most” responses for each of the four scales (D, i, S, and C).
Graph 2: These are your “Least” responses for each of the four scales.
Graph 3: This graph is the result of combining your “Most” choices with your “Least” choices and is used to determine your highest DiSC dimension, Intensity Index scores, and Classical Profile Pattern. (Graph 3 is automatically included in the Online DiSC Classic 2.0 and DiSC Classic 2 Plus Reports).
Tally Box Scores: Shows a summary and the differences of your “Most” and “Least” choices for each of the scales.
Subtitles 3 2 5 download free. When assigning an access code for the Online DiSC Classic 2.0 or DiSC Classic 2 Plus Reports, you’ll see the Report Options below:
Depending on the options selected above the resulting DiSC report will include one of 4 configurations:
Graph 3 only
Graph 3 and Tally Box Scores
Graphs 1, 2, and 3
Graphs 1, 2, 3, and Tally Box Scores
Just check the options that you prefer to include or exclude from your DiSC Profiles.
Graph 3 only
Graph 3 and Tally Box Scores
Graphs 1, 2, and 3
Graphs 1, 2, 3, and Tally Box Scores
Just check the options that you prefer to include or exclude from your DiSC Profiles.
Caveman world mountains of unga boonga download free. Questions about DiSC?
Call 1-800-278-1292
Call 1-800-278-1292
Prove That 2-1
This one is a bit of a stretch to explain without being able to diagram as I, but I'll describe the solution, and you draw the sketch, OK?
!st let's agree to have the plane of the disk coincide with the x-y plane with it's center at the origin. This will make the axis through the center of the disk, and perpendicular to it the z-axis. We wish to find an expression for the electric field at some point P along the z-axis at a distance 'z' from the origin. Draw a disk with radius R in the x-y plane with the z-axis through the center and label your point P.
The electric field is defined by Er= kq/r². We are not given the total charge q on the disk, but we are given the charge density σ and the total charge will be q = σ·A, where A = 2πr².
Now draw a second circle on the disk and about the origin, some dist r away from the origin such that 0<r<R.
Now draw one more circle slightly larger than this at a distance r+dr. This gives us a circular ring of charge a distance r away from the origin which has a length of 2πr and width dr. The area of this ring of charge is going to be: dA = 2πrdr.
Disk Graph 2 1 15 Mm Lead
We're going to need to integrate over the surface of the disk from r = 0 to r = R to get the total contribution form all the surface charge elements to get the field at P. We can do this by noting that:
dE = kdq/r², but dq = σ·dA = 2πrσdr
2-1 Windows
So we can now write: dE = 2πkσrdr/r²
But the r we've written here is for the radius of the disk from the origin out to where r = R. We need to relate this to the distance to our point P on the z-axis.
We first note that the distance z from the origin to point P is at 90° to the plane of the disk and therefore at 90° to our radius vector r which points to the small charge element dq which lies at the location of our ring element dr on the disk. The distance from this element dq to our point P is the length of the hypotenuse of the right triangle we just described: so our r² in the denominator becomes: (z²+r²).
We still have an r in the numerator to consider. Think about what happens as be keep drawing lines from the circumference of our circle to the point P. All of the components dE of our electric field cancel in the x-y plane, leaving only the components rcosθ which parallel the z-axis. (θ is the angle at point P between the z-axis and the line from charge element at dr to point P.
rcosΘ is then = z/(z²+r²)½. We can now write that
dE = 2πkσz·(z²+r²)-3/2 dr
I will leave it to you to perform the integration from r = 0 to R, but you should get:
E = 2πkσ[1-z/(z²+R²)½]
Plug in you values for R and z to complete your solutions.
Dalia S.
Disk Graph 2 1 15 Mm Diameter
thank you for you explanation, its a bit difficult to imagine the diagram but i think i got a good understanding of it. What would be values for R and z? Would you mind solving (a) so i can see how you go about doing it and i will proceed with the rest of the question.
ReportDisk Graph 2 1 15 Mm Hook
09/16/14